Base | Representation |
---|---|
bin | 11001110000111000010000… |
… | …010101010101100110101011 |
3 | 112212012100011202222211200121 |
4 | 121300320100111111212223 |
5 | 104322433041403411133 |
6 | 1040553535240544111 |
7 | 32603245636664362 |
oct | 3160702025254653 |
9 | 485170152884617 |
10 | 113310101232043 |
11 | 331165a9180321 |
12 | 1086030b782037 |
13 | 4b2c1345a2931 |
14 | 1dda3497307d9 |
15 | d176c831d02d |
hex | 670e105559ab |
113310101232043 has 2 divisors, whose sum is σ = 113310101232044. Its totient is φ = 113310101232042.
The previous prime is 113310101231959. The next prime is 113310101232047. The reversal of 113310101232043 is 340232101013311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113310101232043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113310101231999 and 113310101232017.
It is not a weakly prime, because it can be changed into another prime (113310101232047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56655050616021 + 56655050616022.
It is an arithmetic number, because the mean of its divisors is an integer number (56655050616022).
Almost surely, 2113310101232043 is an apocalyptic number.
113310101232043 is a deficient number, since it is larger than the sum of its proper divisors (1).
113310101232043 is an equidigital number, since it uses as much as digits as its factorization.
113310101232043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 113310101232043 its reverse (340232101013311), we get a palindrome (453542202245354).
The spelling of 113310101232043 in words is "one hundred thirteen trillion, three hundred ten billion, one hundred one million, two hundred thirty-two thousand, forty-three".
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