Base | Representation |
---|---|
bin | 1010010011100011010100… |
… | …0101000001000010001011 |
3 | 1111010020022212100001021011 |
4 | 2210320311011001002023 |
5 | 2441121404120444001 |
6 | 40033221315224351 |
7 | 2246432044562005 |
oct | 244706505010213 |
9 | 44106285301234 |
10 | 11331014234251 |
11 | 3679502155468 |
12 | 13300398a80b7 |
13 | 642682799b5a |
14 | 2b25d16d7375 |
15 | 149b2ba35d51 |
hex | a4e3514108b |
11331014234251 has 2 divisors, whose sum is σ = 11331014234252. Its totient is φ = 11331014234250.
The previous prime is 11331014234219. The next prime is 11331014234269. The reversal of 11331014234251 is 15243241013311.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11331014234251 - 25 = 11331014234219 is a prime.
It is not a weakly prime, because it can be changed into another prime (11331014234201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665507117125 + 5665507117126.
It is an arithmetic number, because the mean of its divisors is an integer number (5665507117126).
Almost surely, 211331014234251 is an apocalyptic number.
11331014234251 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331014234251 is an equidigital number, since it uses as much as digits as its factorization.
11331014234251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 11331014234251 its reverse (15243241013311), we get a palindrome (26574255247562).
The spelling of 11331014234251 in words is "eleven trillion, three hundred thirty-one billion, fourteen million, two hundred thirty-four thousand, two hundred fifty-one".
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