Base | Representation |
---|---|
bin | 110100110000111010… |
… | …0100100011000001111 |
3 | 101211110210100122220211 |
4 | 1221201310210120033 |
5 | 3324024420221033 |
6 | 124015401223251 |
7 | 11120635554406 |
oct | 1514164443017 |
9 | 354423318824 |
10 | 113310320143 |
11 | 440667a3689 |
12 | 19b63491b27 |
13 | a8ba283717 |
14 | 56acac863d |
15 | 2e32a382cd |
hex | 1a61d2460f |
113310320143 has 2 divisors, whose sum is σ = 113310320144. Its totient is φ = 113310320142.
The previous prime is 113310320047. The next prime is 113310320147. The reversal of 113310320143 is 341023013311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113310320143 is a prime.
It is a super-3 number, since 3×1133103201433 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113310320147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56655160071 + 56655160072.
It is an arithmetic number, because the mean of its divisors is an integer number (56655160072).
Almost surely, 2113310320143 is an apocalyptic number.
113310320143 is a deficient number, since it is larger than the sum of its proper divisors (1).
113310320143 is an equidigital number, since it uses as much as digits as its factorization.
113310320143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 113310320143 its reverse (341023013311), we get a palindrome (454333333454).
The spelling of 113310320143 in words is "one hundred thirteen billion, three hundred ten million, three hundred twenty thousand, one hundred forty-three".
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