Base | Representation |
---|---|
bin | 11001110000111001000110… |
… | …101011100010011010010010 |
3 | 112212012102112022200112110012 |
4 | 121300321012223202122102 |
5 | 104322441423313140310 |
6 | 1040554205531434522 |
7 | 32603310351034235 |
oct | 3160710653423222 |
9 | 485172468615405 |
10 | 113311013021330 |
11 | 33116a26925093 |
12 | 10860524bb5a42 |
13 | 4b2c24b466417 |
14 | 1dda3d487941c |
15 | d1772d3c7c05 |
hex | 670e46ae2692 |
113311013021330 has 32 divisors (see below), whose sum is σ = 210605653463040. Its totient is φ = 43848477437760.
The previous prime is 113311013021287. The next prime is 113311013021347. The reversal of 113311013021330 is 33120310113311.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 113311013021296 and 113311013021305.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 56725745 + ... + 58689284.
It is an arithmetic number, because the mean of its divisors is an integer number (6581426670720).
Almost surely, 2113311013021330 is an apocalyptic number.
113311013021330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113311013021330 is a deficient number, since it is larger than the sum of its proper divisors (97294640441710).
113311013021330 is a wasteful number, since it uses less digits than its factorization.
113311013021330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 115418234.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 113311013021330 its reverse (33120310113311), we get a palindrome (146431323134641).
The spelling of 113311013021330 in words is "one hundred thirteen trillion, three hundred eleven billion, thirteen million, twenty-one thousand, three hundred thirty".
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