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11331102013081 is a prime number
BaseRepresentation
bin1010010011100011101001…
…0011110111011010011001
31111010020112222111200011221
42210320322103313122121
52441122044103404311
640033234132452041
72246434161643654
oct244707223673231
944106488450157
1011331102013081
113679547759a54
12133006317a021
13642697a21aa6
142b25dd22689b
15149b345c4671
hexa4e3a4f7699

11331102013081 has 2 divisors, whose sum is σ = 11331102013082. Its totient is φ = 11331102013080.

The previous prime is 11331102013073. The next prime is 11331102013109. The reversal of 11331102013081 is 18031020113311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10480169561481 + 850932451600 = 3237309^2 + 922460^2 .

It is an emirp because it is prime and its reverse (18031020113311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11331102013081 - 23 = 11331102013073 is a prime.

It is a super-2 number, since 2×113311020130812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11331102013381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665551006540 + 5665551006541.

It is an arithmetic number, because the mean of its divisors is an integer number (5665551006541).

Almost surely, 211331102013081 is an apocalyptic number.

It is an amenable number.

11331102013081 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331102013081 is an equidigital number, since it uses as much as digits as its factorization.

11331102013081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 25.

Adding to 11331102013081 its reverse (18031020113311), we get a palindrome (29362122126392).

The spelling of 11331102013081 in words is "eleven trillion, three hundred thirty-one billion, one hundred two million, thirteen thousand, eighty-one".