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11331121201305 = 352332843829569
BaseRepresentation
bin1010010011100011101101…
…1101000100000010011001
31111010020121022121112110220
42210320323131010002121
52441122114011420210
640033240100030253
72246434514022213
oct244707335040231
944106538545426
1011331121201305
113679557575394
121330069692389
1364269b9ac879
142b26019bd5b3
15149b36114c70
hexa4e3b744099

11331121201305 has 16 divisors (see below), whose sum is σ = 18918045832320. Its totient is φ = 5780514003968.

The previous prime is 11331121201297. The next prime is 11331121201319. The reversal of 11331121201305 is 50310212113311.

It is a cyclic number.

It is not a de Polignac number, because 11331121201305 - 23 = 11331121201297 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16421914440 + ... + 16421915129.

It is an arithmetic number, because the mean of its divisors is an integer number (1182377864520).

Almost surely, 211331121201305 is an apocalyptic number.

11331121201305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

11331121201305 is a deficient number, since it is larger than the sum of its proper divisors (7586924631015).

11331121201305 is a wasteful number, since it uses less digits than its factorization.

11331121201305 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32843829600.

The product of its (nonzero) digits is 540, while the sum is 24.

Adding to 11331121201305 its reverse (50310212113311), we get a palindrome (61641333314616).

The spelling of 11331121201305 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-one million, two hundred one thousand, three hundred five".

Divisors: 1 3 5 15 23 69 115 345 32843829569 98531488707 164219147845 492657443535 755408080087 2266224240261 3777040400435 11331121201305