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11331122099893 is a prime number
BaseRepresentation
bin1010010011100011101110…
…0000011111011010110101
31111010020121101022012002221
42210320323200133122311
52441122114224144033
640033240131202341
72246434524454051
oct244707340373265
944106541265087
1011331122099893
113679558029522
121330069a463b1
1364269bc3588b
142b2601b74c61
15149b3624112d
hexa4e3b81f6b5

11331122099893 has 2 divisors, whose sum is σ = 11331122099894. Its totient is φ = 11331122099892.

The previous prime is 11331122099863. The next prime is 11331122099929. The reversal of 11331122099893 is 39899022113311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9853810690084 + 1477311409809 = 3139078^2 + 1215447^2 .

It is a cyclic number.

It is not a de Polignac number, because 11331122099893 - 25 = 11331122099861 is a prime.

It is a super-2 number, since 2×113311220998932 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11331122099893.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331122099833) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665561049946 + 5665561049947.

It is an arithmetic number, because the mean of its divisors is an integer number (5665561049947).

Almost surely, 211331122099893 is an apocalyptic number.

It is an amenable number.

11331122099893 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331122099893 is an equidigital number, since it uses as much as digits as its factorization.

11331122099893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 629856, while the sum is 52.

The spelling of 11331122099893 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-two million, ninety-nine thousand, eight hundred ninety-three".