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11331122229967 is a prime number
BaseRepresentation
bin1010010011100011101110…
…0000111111001011001111
31111010020121101112210112111
42210320323200333023033
52441122114242324332
640033240134044451
72246434525535221
oct244707340771317
944106541483474
1011331122229967
113679558108221
121330069aa9727
1364269bc7cb47
142b2601baa411
15149b36269947
hexa4e3b83f2cf

11331122229967 has 2 divisors, whose sum is σ = 11331122229968. Its totient is φ = 11331122229966.

The previous prime is 11331122229901. The next prime is 11331122229979. The reversal of 11331122229967 is 76992222113311.

It is a strong prime.

It is an emirp because it is prime and its reverse (76992222113311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11331122229967 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 11331122229967.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331122229997) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665561114983 + 5665561114984.

It is an arithmetic number, because the mean of its divisors is an integer number (5665561114984).

Almost surely, 211331122229967 is an apocalyptic number.

11331122229967 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331122229967 is an equidigital number, since it uses as much as digits as its factorization.

11331122229967 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 489888, while the sum is 49.

The spelling of 11331122229967 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-two million, two hundred twenty-nine thousand, nine hundred sixty-seven".