Base | Representation |
---|---|
bin | 1010010011100011101110… |
… | …0000111111011011010001 |
3 | 1111010020121101112211221111 |
4 | 2210320323200333123101 |
5 | 2441122114242342433 |
6 | 40033240134053321 |
7 | 2246434525541215 |
oct | 244707340773321 |
9 | 44106541484844 |
10 | 11331122230993 |
11 | 3679558108a74 |
12 | 1330069aaa241 |
13 | 64269bc80456 |
14 | 2b2601baa945 |
15 | 149b36269dcd |
hex | a4e3b83f6d1 |
11331122230993 has 2 divisors, whose sum is σ = 11331122230994. Its totient is φ = 11331122230992.
The previous prime is 11331122230973. The next prime is 11331122231003. The reversal of 11331122230993 is 39903222113311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10868052868929 + 463069362064 = 3296673^2 + 680492^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11331122230993 is a prime.
It is not a weakly prime, because it can be changed into another prime (11331122230973) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665561115496 + 5665561115497.
It is an arithmetic number, because the mean of its divisors is an integer number (5665561115497).
Almost surely, 211331122230993 is an apocalyptic number.
It is an amenable number.
11331122230993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331122230993 is an equidigital number, since it uses as much as digits as its factorization.
11331122230993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 52488, while the sum is 40.
The spelling of 11331122230993 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-two million, two hundred thirty thousand, nine hundred ninety-three".
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