Base | Representation |
---|---|
bin | 1010010011100011101110… |
… | …0000111111011011011011 |
3 | 1111010020121101112211221212 |
4 | 2210320323200333123123 |
5 | 2441122114242343003 |
6 | 40033240134053335 |
7 | 2246434525541231 |
oct | 244707340773333 |
9 | 44106541484855 |
10 | 11331122231003 |
11 | 3679558108a83 |
12 | 1330069aaa24b |
13 | 64269bc80463 |
14 | 2b2601baa951 |
15 | 149b36269dd8 |
hex | a4e3b83f6db |
11331122231003 has 2 divisors, whose sum is σ = 11331122231004. Its totient is φ = 11331122231002.
The previous prime is 11331122230993. The next prime is 11331122231063. The reversal of 11331122231003 is 30013222113311.
It is a weak prime.
It is an emirp because it is prime and its reverse (30013222113311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11331122231003 - 210 = 11331122229979 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11331122231003.
It is not a weakly prime, because it can be changed into another prime (11331122231063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665561115501 + 5665561115502.
It is an arithmetic number, because the mean of its divisors is an integer number (5665561115502).
Almost surely, 211331122231003 is an apocalyptic number.
11331122231003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331122231003 is an equidigital number, since it uses as much as digits as its factorization.
11331122231003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 11331122231003 its reverse (30013222113311), we get a palindrome (41344344344314).
The spelling of 11331122231003 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-two million, two hundred thirty-one thousand, three".
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