Base | Representation |
---|---|
bin | 1010010011100011101111… |
… | …1111011100001001110011 |
3 | 1111010020121221120101011121 |
4 | 2210320323333130021303 |
5 | 2441122123313303404 |
6 | 40033241021123111 |
7 | 2246434653434263 |
oct | 244707377341163 |
9 | 44106557511147 |
10 | 11331130212979 |
11 | 367956166aa55 |
12 | 13300706b9497 |
13 | 6426a0816615 |
14 | 2b2602c877a3 |
15 | 149b36ce4e54 |
hex | a4e3bfdc273 |
11331130212979 has 2 divisors, whose sum is σ = 11331130212980. Its totient is φ = 11331130212978.
The previous prime is 11331130212977. The next prime is 11331130212991. The reversal of 11331130212979 is 97921203113311.
It is a weak prime.
It is an emirp because it is prime and its reverse (97921203113311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11331130212979 - 21 = 11331130212977 is a prime.
Together with 11331130212977, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11331130212977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565106489 + 5665565106490.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565106490).
Almost surely, 211331130212979 is an apocalyptic number.
11331130212979 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331130212979 is an equidigital number, since it uses as much as digits as its factorization.
11331130212979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61236, while the sum is 43.
The spelling of 11331130212979 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty million, two hundred twelve thousand, nine hundred seventy-nine".
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