11331131013127 has 2 divisors, whose sum is σ = 11331131013128. Its totient is φ = 11331131013126.

The previous prime is 11331131013077. The next prime is 11331131013211. The reversal of 11331131013127 is 72131013113311.

It is a weak prime.

It is an emirp because it is prime and its reverse (72131013113311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11331131013127 - 2³⁵ = 11296771274759 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11331131013095 and 11331131013104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331131010127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565506563 + 5665565506564.

It is an arithmetic number, because the mean of its divisors is an integer number (5665565506564).

Almost surely, 2^{11331131013127} is an apocalyptic number.

11331131013127 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331131013127 is an equidigital number, since it uses as much as digits as its factorization.

11331131013127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1134, while the sum is 28.

Adding to 11331131013127 its reverse (72131013113311), we get a palindrome (83462144126438).

The spelling of 11331131013127 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, thirteen thousand, one hundred twenty-seven".