Base | Representation |
---|---|
bin | 10000011111010010110… |
… | …011011100111100101001 |
3 | 11000022202121012122101102 |
4 | 100133102303130330221 |
5 | 122031103423231441 |
6 | 2224313414131145 |
7 | 144602412310610 |
oct | 20372263347451 |
9 | 4008677178342 |
10 | 1133113102121 |
11 | 3a76068957a0 |
12 | 163731350ab5 |
13 | 82b10104c20 |
14 | 3cbb315a877 |
15 | 1e71ca6069b |
hex | 107d2cdcf29 |
1133113102121 has 64 divisors (see below), whose sum is σ = 1545222873600. Its totient is φ = 802335283200.
The previous prime is 1133113102087. The next prime is 1133113102133. The reversal of 1133113102121 is 1212013113311.
It is a de Polignac number, because none of the positive numbers 2k-1133113102121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1133113102093 and 1133113102102.
It is not an unprimeable number, because it can be changed into a prime (1133113102421) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 20373611 + ... + 20429151.
It is an arithmetic number, because the mean of its divisors is an integer number (24144107400).
Almost surely, 21133113102121 is an apocalyptic number.
1133113102121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
1133113102121 is a deficient number, since it is larger than the sum of its proper divisors (412109771479).
1133113102121 is a wasteful number, since it uses less digits than its factorization.
1133113102121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55890.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 1133113102121 its reverse (1212013113311), we get a palindrome (2345126215432).
The spelling of 1133113102121 in words is "one trillion, one hundred thirty-three billion, one hundred thirteen million, one hundred two thousand, one hundred twenty-one".
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