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1133113102421 is a prime number
BaseRepresentation
bin10000011111010010110…
…011011101000001010101
311000022202121012122210112
4100133102303131001111
5122031103423234141
62224313414132405
7144602412311516
oct20372263350125
94008677178715
101133113102421
113a7606895a43
12163731351105
1382b101050c1
143cbb315aa0d
151e71ca607eb
hex107d2cdd055

1133113102421 has 2 divisors, whose sum is σ = 1133113102422. Its totient is φ = 1133113102420.

The previous prime is 1133113102337. The next prime is 1133113102423. The reversal of 1133113102421 is 1242013113311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1127077366321 + 6035736100 = 1061639^2 + 77690^2 .

It is a cyclic number.

It is not a de Polignac number, because 1133113102421 - 226 = 1133045993557 is a prime.

It is a super-2 number, since 2×11331131024212 (a number of 25 digits) contains 22 as substring.

Together with 1133113102423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1133113102423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566556551210 + 566556551211.

It is an arithmetic number, because the mean of its divisors is an integer number (566556551211).

Almost surely, 21133113102421 is an apocalyptic number.

It is an amenable number.

1133113102421 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133113102421 is an equidigital number, since it uses as much as digits as its factorization.

1133113102421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1133113102421 its reverse (1242013113311), we get a palindrome (2375126215732).

The spelling of 1133113102421 in words is "one trillion, one hundred thirty-three billion, one hundred thirteen million, one hundred two thousand, four hundred twenty-one".