1133113102133 has 2 divisors, whose sum is σ = 1133113102134. Its totient is φ = 1133113102132.

The previous prime is 1133113102087. The next prime is 1133113102183. The reversal of 1133113102133 is 3312013113311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 973977531409 + 159135570724 = 986903^2 + 398918^2 .

It is a cyclic number.

It is not a de Polignac number, because 1133113102133 - 2¹² = 1133113098037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1133113102099 and 1133113102108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1133113102183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566556551066 + 566556551067.

It is an arithmetic number, because the mean of its divisors is an integer number (566556551067).

Almost surely, 2^{1133113102133} is an apocalyptic number.

It is an amenable number.

1133113102133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133113102133 is an equidigital number, since it uses as much as digits as its factorization.

1133113102133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 1133113102133 its reverse (3312013113311), we get a palindrome (4445126215444).

The spelling of 1133113102133 in words is "one trillion, one hundred thirty-three billion, one hundred thirteen million, one hundred two thousand, one hundred thirty-three".