Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0011001101101011111101 |
3 | 1111010020122000102122021011 |
4 | 2210320330003031223331 |
5 | 2441122124041433201 |
6 | 40033241054235221 |
7 | 2246434665024511 |
oct | 244707403155375 |
9 | 44106560378234 |
10 | 11331131202301 |
11 | 3679562186279 |
12 | 1330070ab5b11 |
13 | 6426a0aa1a11 |
14 | 2b2603064141 |
15 | 149b36e3d151 |
hex | a4e3c0cdafd |
11331131202301 has 2 divisors, whose sum is σ = 11331131202302. Its totient is φ = 11331131202300.
The previous prime is 11331131202283. The next prime is 11331131202311. The reversal of 11331131202301 is 10320213113311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9886685376100 + 1444445826201 = 3144310^2 + 1201851^2 .
It is a cyclic number.
It is not a de Polignac number, because 11331131202301 - 25 = 11331131202269 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331131202311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565601150 + 5665565601151.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565601151).
Almost surely, 211331131202301 is an apocalyptic number.
It is an amenable number.
11331131202301 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331131202301 is an equidigital number, since it uses as much as digits as its factorization.
11331131202301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 11331131202301 its reverse (10320213113311), we get a palindrome (21651344315612).
The spelling of 11331131202301 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, two hundred two thousand, three hundred one".
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