Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0011010010100001100001 |
3 | 1111010020122000110122102221 |
4 | 2210320330003102201201 |
5 | 2441122124043101423 |
6 | 40033241054511041 |
7 | 2246434665136333 |
oct | 244707403224141 |
9 | 44106560418387 |
10 | 11331131222113 |
11 | 367956219a14a |
12 | 1330070b05481 |
13 | 6426a0aaaa41 |
14 | 2b260306b453 |
15 | 149b36e43e5d |
hex | a4e3c0d2861 |
11331131222113 has 2 divisors, whose sum is σ = 11331131222114. Its totient is φ = 11331131222112.
The previous prime is 11331131222071. The next prime is 11331131222161. The reversal of 11331131222113 is 31122213113311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9983470273569 + 1347660948544 = 3159663^2 + 1160888^2 .
It is a cyclic number.
It is not a de Polignac number, because 11331131222113 - 221 = 11331129124961 is a prime.
It is not a weakly prime, because it can be changed into another prime (11331131222183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565611056 + 5665565611057.
It is an arithmetic number, because the mean of its divisors is an integer number (5665565611057).
Almost surely, 211331131222113 is an apocalyptic number.
It is an amenable number.
11331131222113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331131222113 is an equidigital number, since it uses as much as digits as its factorization.
11331131222113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 648, while the sum is 25.
Adding to 11331131222113 its reverse (31122213113311), we get a palindrome (42453344335424).
The spelling of 11331131222113 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, two hundred twenty-two thousand, one hundred thirteen".
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