1133113199747 has 2 divisors, whose sum is σ = 1133113199748. Its totient is φ = 1133113199746.

The previous prime is 1133113199719. The next prime is 1133113199749. The reversal of 1133113199747 is 7479913113311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1133113199747 is a prime.

Together with 1133113199749, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1133113199695 and 1133113199704.

It is not a weakly prime, because it can be changed into another prime (1133113199749) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566556599873 + 566556599874.

It is an arithmetic number, because the mean of its divisors is an integer number (566556599874).

Almost surely, 2^{1133113199747} is an apocalyptic number.

1133113199747 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133113199747 is an equidigital number, since it uses as much as digits as its factorization.

1133113199747 is an evil number, because the sum of its binary digits is even.

The product of its digits is 428652, while the sum is 50.

The spelling of 1133113199747 in words is "one trillion, one hundred thirty-three billion, one hundred thirteen million, one hundred ninety-nine thousand, seven hundred forty-seven".