11331132000031 has 2 divisors, whose sum is σ = 11331132000032. Its totient is φ = 11331132000030.

The previous prime is 11331131999981. The next prime is 11331132000061. The reversal of 11331132000031 is 13000023113311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11331132000031 - 2⁷ = 11331131999903 is a prime.

It is a super-2 number, since 2×11331132000031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11331131999972 and 11331132000008.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331132000061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665566000015 + 5665566000016.

It is an arithmetic number, because the mean of its divisors is an integer number (5665566000016).

Almost surely, 2^{11331132000031} is an apocalyptic number.

11331132000031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331132000031 is an equidigital number, since it uses as much as digits as its factorization.

11331132000031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11331132000031 its reverse (13000023113311), we get a palindrome (24331155113342).

The spelling of 11331132000031 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, thirty-one", and thus it is an aban number.