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11331132009973 is a prime number
BaseRepresentation
bin1010010011100011110000…
…0110010010110111110101
31111010020122001221200011221
42210320330012102313311
52441122124243304343
640033241123430341
72246435004630316
oct244707406226765
944106561850157
1011331132009973
113679562688076
1213300712253b1
136426a0cc5529
142b26031d460d
15149b3704c5ed
hexa4e3c192df5

11331132009973 has 2 divisors, whose sum is σ = 11331132009974. Its totient is φ = 11331132009972.

The previous prime is 11331132009943. The next prime is 11331132010021. The reversal of 11331132009973 is 37990023113311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10264955986609 + 1066176023364 = 3203897^2 + 1032558^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11331132009973 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331132009943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665566004986 + 5665566004987.

It is an arithmetic number, because the mean of its divisors is an integer number (5665566004987).

Almost surely, 211331132009973 is an apocalyptic number.

It is an amenable number.

11331132009973 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331132009973 is an equidigital number, since it uses as much as digits as its factorization.

11331132009973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 91854, while the sum is 43.

The spelling of 11331132009973 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, nine thousand, nine hundred seventy-three".