Base | Representation |
---|---|
bin | 1010010011100011110000… |
… | …0110101101110011011011 |
3 | 1111010020122002011021111111 |
4 | 2210320330012231303123 |
5 | 2441122124310322113 |
6 | 40033241130041151 |
7 | 2246435005600033 |
oct | 244707406556333 |
9 | 44106562137444 |
10 | 11331132120283 |
11 | 3679562752a38 |
12 | 13300712791b7 |
13 | 6426a10337c1 |
14 | 2b26032228c3 |
15 | 149b3707013d |
hex | a4e3c1adcdb |
11331132120283 has 2 divisors, whose sum is σ = 11331132120284. Its totient is φ = 11331132120282.
The previous prime is 11331132120281. The next prime is 11331132120311. The reversal of 11331132120283 is 38202123113311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11331132120283 - 21 = 11331132120281 is a prime.
Together with 11331132120281, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (11331132120281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665566060141 + 5665566060142.
It is an arithmetic number, because the mean of its divisors is an integer number (5665566060142).
Almost surely, 211331132120283 is an apocalyptic number.
11331132120283 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331132120283 is an equidigital number, since it uses as much as digits as its factorization.
11331132120283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 31.
Adding to 11331132120283 its reverse (38202123113311), we get a palindrome (49533255233594).
The spelling of 11331132120283 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-two million, one hundred twenty thousand, two hundred eighty-three".
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