Base | Representation |
---|---|
bin | 110100110000111101… |
… | …0110011001000011111 |
3 | 101211110220102122101021 |
4 | 1221201322303020133 |
5 | 3324030330002224 |
6 | 124015500225011 |
7 | 11120655466246 |
oct | 1514172631037 |
9 | 354426378337 |
10 | 113311953439 |
11 | 44067709813 |
12 | 19b63b3b167 |
13 | a8ba705c79 |
14 | 56acdd195d |
15 | 2e32c5c1e4 |
hex | 1a61eb321f |
113311953439 has 2 divisors, whose sum is σ = 113311953440. Its totient is φ = 113311953438.
The previous prime is 113311953409. The next prime is 113311953449. The reversal of 113311953439 is 934359113311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113311953439 - 25 = 113311953407 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113311953395 and 113311953404.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113311953409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56655976719 + 56655976720.
It is an arithmetic number, because the mean of its divisors is an integer number (56655976720).
Almost surely, 2113311953439 is an apocalyptic number.
113311953439 is a deficient number, since it is larger than the sum of its proper divisors (1).
113311953439 is an equidigital number, since it uses as much as digits as its factorization.
113311953439 is an evil number, because the sum of its binary digits is even.
The product of its digits is 131220, while the sum is 43.
The spelling of 113311953439 in words is "one hundred thirteen billion, three hundred eleven million, nine hundred fifty-three thousand, four hundred thirty-nine".
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