Base | Representation |
---|---|
bin | 1010010011100100000000… |
… | …1110001100110010101001 |
3 | 1111010020210220010102211012 |
4 | 2210321000032030302221 |
5 | 2441122300001103311 |
6 | 40033252034313305 |
7 | 2246436504643442 |
oct | 244710016146251 |
9 | 44106726112735 |
10 | 11331201191081 |
11 | 3679598739942 |
12 | 1330090428835 |
13 | 6426b24383b5 |
14 | 2b260c4822c9 |
15 | 149b3d16578b |
hex | a4e4038cca9 |
11331201191081 has 2 divisors, whose sum is σ = 11331201191082. Its totient is φ = 11331201191080.
The previous prime is 11331201191071. The next prime is 11331201191111. The reversal of 11331201191081 is 18019110213311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10696438432681 + 634762758400 = 3270541^2 + 796720^2 .
It is a cyclic number.
It is not a de Polignac number, because 11331201191081 - 226 = 11331134082217 is a prime.
It is a super-3 number, since 3×113312011910813 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (11331201191041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665600595540 + 5665600595541.
It is an arithmetic number, because the mean of its divisors is an integer number (5665600595541).
Almost surely, 211331201191081 is an apocalyptic number.
It is an amenable number.
11331201191081 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331201191081 is an equidigital number, since it uses as much as digits as its factorization.
11331201191081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 32.
The spelling of 11331201191081 in words is "eleven trillion, three hundred thirty-one billion, two hundred one million, one hundred ninety-one thousand, eighty-one".
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