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1133120121307 is a prime number
BaseRepresentation
bin10000011111010011001…
…110001110100111011011
311000022210002102020220021
4100133103032032213123
5122031112222340212
62224314224411311
7144602526053656
oct20372316164733
94008702366807
101133120121307
113a760a84a379
12163733776b37
1382b116c1aa5
143cbb406689d
151e71d49a307
hex107d338e9db

1133120121307 has 2 divisors, whose sum is σ = 1133120121308. Its totient is φ = 1133120121306.

The previous prime is 1133120121281. The next prime is 1133120121317. The reversal of 1133120121307 is 7031210213311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1133120121307 - 27 = 1133120121179 is a prime.

It is a super-2 number, since 2×11331201213072 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1133120121317) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566560060653 + 566560060654.

It is an arithmetic number, because the mean of its divisors is an integer number (566560060654).

Almost surely, 21133120121307 is an apocalyptic number.

1133120121307 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133120121307 is an equidigital number, since it uses as much as digits as its factorization.

1133120121307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 1133120121307 its reverse (7031210213311), we get a palindrome (8164330334618).

The spelling of 1133120121307 in words is "one trillion, one hundred thirty-three billion, one hundred twenty million, one hundred twenty-one thousand, three hundred seven".