Base | Representation |
---|---|
bin | 110100110000111101… |
… | …1000011111001110101 |
3 | 101211110220120010121111 |
4 | 1221201323003321311 |
5 | 3324030334202013 |
6 | 124015501515021 |
7 | 11120656203442 |
oct | 1514173037165 |
9 | 354426503544 |
10 | 113312022133 |
11 | 44067756392 |
12 | 19b63b72a71 |
13 | a8ba72b30b |
14 | 56ad00c9c9 |
15 | 2e32c7273d |
hex | 1a61ec3e75 |
113312022133 has 2 divisors, whose sum is σ = 113312022134. Its totient is φ = 113312022132.
The previous prime is 113312022119. The next prime is 113312022149. The reversal of 113312022133 is 331220213311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98349350449 + 14962671684 = 313607^2 + 122322^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113312022133 is a prime.
It is a super-2 number, since 2×1133120221332 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113312022533) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56656011066 + 56656011067.
It is an arithmetic number, because the mean of its divisors is an integer number (56656011067).
Almost surely, 2113312022133 is an apocalyptic number.
It is an amenable number.
113312022133 is a deficient number, since it is larger than the sum of its proper divisors (1).
113312022133 is an equidigital number, since it uses as much as digits as its factorization.
113312022133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 113312022133 its reverse (331220213311), we get a palindrome (444532235444).
The spelling of 113312022133 in words is "one hundred thirteen billion, three hundred twelve million, twenty-two thousand, one hundred thirty-three".
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