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113312222012173 is a prime number
BaseRepresentation
bin11001110000111010001110…
…101111011110001100001101
3112212012112122120121122002211
4121300322032233132030031
5104323001412313342143
61040554525520350421
732603352331220002
oct3160721657361415
9485175576548084
10113312222012173
1133117497311878
1210860801a75411
134b2c3b1a88012
141dda4ab2698a9
15d1779e5dc49d
hex670e8ebde30d

113312222012173 has 2 divisors, whose sum is σ = 113312222012174. Its totient is φ = 113312222012172.

The previous prime is 113312222012149. The next prime is 113312222012293. The reversal of 113312222012173 is 371210222213311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 59905401860164 + 53406820152009 = 7739858^2 + 7307997^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113312222012173 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113312222015173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56656111006086 + 56656111006087.

It is an arithmetic number, because the mean of its divisors is an integer number (56656111006087).

Almost surely, 2113312222012173 is an apocalyptic number.

It is an amenable number.

113312222012173 is a deficient number, since it is larger than the sum of its proper divisors (1).

113312222012173 is an equidigital number, since it uses as much as digits as its factorization.

113312222012173 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 113312222012173 its reverse (371210222213311), we get a palindrome (484522444225484).

The spelling of 113312222012173 in words is "one hundred thirteen trillion, three hundred twelve billion, two hundred twenty-two million, twelve thousand, one hundred seventy-three".