Base | Representation |
---|---|
bin | 11001110000111010111101… |
… | …001100001110100001001011 |
3 | 112212012121122212222122220101 |
4 | 121300322331030032201023 |
5 | 104323010011313131331 |
6 | 1040555135115310231 |
7 | 32603410543116163 |
oct | 3160727514164113 |
9 | 485177585878811 |
10 | 113313001302091 |
11 | 33117857197928 |
12 | 1086099aa4b377 |
13 | 4b2c4a7369506 |
14 | 1dda5429635a3 |
15 | d177e7c23061 |
hex | 670ebd30e84b |
113313001302091 has 2 divisors, whose sum is σ = 113313001302092. Its totient is φ = 113313001302090.
The previous prime is 113313001301987. The next prime is 113313001302101. The reversal of 113313001302091 is 190203100313311.
It is a strong prime.
It is an emirp because it is prime and its reverse (190203100313311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113313001302091 is a prime.
It is a super-2 number, since 2×1133130013020912 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (113313001302191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56656500651045 + 56656500651046.
It is an arithmetic number, because the mean of its divisors is an integer number (56656500651046).
Almost surely, 2113313001302091 is an apocalyptic number.
113313001302091 is a deficient number, since it is larger than the sum of its proper divisors (1).
113313001302091 is an equidigital number, since it uses as much as digits as its factorization.
113313001302091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 28.
The spelling of 113313001302091 in words is "one hundred thirteen trillion, three hundred thirteen billion, one million, three hundred two thousand, ninety-one".
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