113313001302101 has 2 divisors, whose sum is σ = 113313001302102. Its totient is φ = 113313001302100.

The previous prime is 113313001302091. The next prime is 113313001302103. The reversal of 113313001302101 is 101203100313311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110119292763076 + 3193708539025 = 10493774^2 + 1787095^2 .

It is a cyclic number.

It is not a de Polignac number, because 113313001302101 - 2¹⁰ = 113313001301077 is a prime.

Together with 113313001302103, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113313001302103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56656500651050 + 56656500651051.

It is an arithmetic number, because the mean of its divisors is an integer number (56656500651051).

Almost surely, 2^{113313001302101} is an apocalyptic number.

It is an amenable number.

113313001302101 is a deficient number, since it is larger than the sum of its proper divisors (1).

113313001302101 is an equidigital number, since it uses as much as digits as its factorization.

113313001302101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 113313001302101 its reverse (101203100313311), we get a palindrome (214516101615412).

The spelling of 113313001302101 in words is "one hundred thirteen trillion, three hundred thirteen billion, one million, three hundred two thousand, one hundred one".