11331321023201 has 2 divisors, whose sum is σ = 11331321023202. Its totient is φ = 11331321023200.

The previous prime is 11331321023173. The next prime is 11331321023203. The reversal of 11331321023201 is 10232012313311.

11331321023201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9290425920400 + 2040895102801 = 3048020^2 + 1428599^2 .

It is an emirp because it is prime and its reverse (10232012313311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11331321023201 - 2⁴² = 6933274512097 is a prime.

It is a super-2 number, since 2×11331321023201² (a number of 27 digits) contains 22 as substring.

Together with 11331321023203, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11331321023203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665660511600 + 5665660511601.

It is an arithmetic number, because the mean of its divisors is an integer number (5665660511601).

Almost surely, 2^{11331321023201} is an apocalyptic number.

It is an amenable number.

11331321023201 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331321023201 is an equidigital number, since it uses as much as digits as its factorization.

11331321023201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 11331321023201 its reverse (10232012313311), we get a palindrome (21563333336512).

The spelling of 11331321023201 in words is "eleven trillion, three hundred thirty-one billion, three hundred twenty-one million, twenty-three thousand, two hundred one".