Base | Representation |
---|---|
bin | 1010010011100100011101… |
… | …1111101101000010101111 |
3 | 1111010021010101202011020002 |
4 | 2210321013133231002233 |
5 | 2441123022221021033 |
6 | 40033312114014515 |
7 | 2246442516115343 |
oct | 244710737550257 |
9 | 44107111664202 |
10 | 11331323220143 |
11 | 3679650607103 |
12 | 133010527743b |
13 | 6427017c2a44 |
14 | 2b2620769623 |
15 | 149b48c1c3e8 |
hex | a4e477ed0af |
11331323220143 has 2 divisors, whose sum is σ = 11331323220144. Its totient is φ = 11331323220142.
The previous prime is 11331323220131. The next prime is 11331323220197. The reversal of 11331323220143 is 34102232313311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11331323220143 - 216 = 11331323154607 is a prime.
It is a super-3 number, since 3×113313232201433 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331323220043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665661610071 + 5665661610072.
It is an arithmetic number, because the mean of its divisors is an integer number (5665661610072).
Almost surely, 211331323220143 is an apocalyptic number.
11331323220143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331323220143 is an equidigital number, since it uses as much as digits as its factorization.
11331323220143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 11331323220143 its reverse (34102232313311), we get a palindrome (45433555533454).
The spelling of 11331323220143 in words is "eleven trillion, three hundred thirty-one billion, three hundred twenty-three million, two hundred twenty thousand, one hundred forty-three".
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