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1133141441293 is a prime number
BaseRepresentation
bin10000011111010100011…
…111100011101100001101
311000022211120112102102101
4100133110133203230031
5122031133202110133
62224320305355101
7144603205221241
oct20372437435415
94008746472371
101133141441293
113a76208913a4
1216373a938a91
1382b15c47c74
143cbb6c16421
151e7202ac37d
hex107d47e3b0d

1133141441293 has 2 divisors, whose sum is σ = 1133141441294. Its totient is φ = 1133141441292.

The previous prime is 1133141441149. The next prime is 1133141441297. The reversal of 1133141441293 is 3921441413311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1111046699844 + 22094741449 = 1054062^2 + 148643^2 .

It is an emirp because it is prime and its reverse (3921441413311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1133141441293 - 225 = 1133107886861 is a prime.

It is a super-3 number, since 3×11331414412933 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1133141441297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566570720646 + 566570720647.

It is an arithmetic number, because the mean of its divisors is an integer number (566570720647).

Almost surely, 21133141441293 is an apocalyptic number.

It is an amenable number.

1133141441293 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133141441293 is an equidigital number, since it uses as much as digits as its factorization.

1133141441293 is an evil number, because the sum of its binary digits is even.

The product of its digits is 31104, while the sum is 37.

The spelling of 1133141441293 in words is "one trillion, one hundred thirty-three billion, one hundred forty-one million, four hundred forty-one thousand, two hundred ninety-three".