Base | Representation |
---|---|
bin | 110100110001001100… |
… | …1111111111000000111 |
3 | 101211111110211011101202 |
4 | 1221202121333320013 |
5 | 3324034423211403 |
6 | 124020351413115 |
7 | 11121115141613 |
oct | 1514231777007 |
9 | 354443734352 |
10 | 113320132103 |
11 | 44071295542 |
12 | 19b6682419b |
13 | a8bc30a809 |
14 | 56b0120343 |
15 | 2e33825688 |
hex | 1a6267fe07 |
113320132103 has 2 divisors, whose sum is σ = 113320132104. Its totient is φ = 113320132102.
The previous prime is 113320132067. The next prime is 113320132147. The reversal of 113320132103 is 301231023311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113320132103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113320182103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56660066051 + 56660066052.
It is an arithmetic number, because the mean of its divisors is an integer number (56660066052).
Almost surely, 2113320132103 is an apocalyptic number.
113320132103 is a deficient number, since it is larger than the sum of its proper divisors (1).
113320132103 is an equidigital number, since it uses as much as digits as its factorization.
113320132103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 113320132103 its reverse (301231023311), we get a palindrome (414551155414).
The spelling of 113320132103 in words is "one hundred thirteen billion, three hundred twenty million, one hundred thirty-two thousand, one hundred three".
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