11332014041 has 2 divisors, whose sum is σ = 11332014042. Its totient is φ = 11332014040.

The previous prime is 11332014019. The next prime is 11332014061. The reversal of 11332014041 is 14041023311.

It is an a-pointer prime, because the next prime (11332014061) can be obtained adding 11332014041 to its sum of digits (20).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8648256016 + 2683758025 = 92996^2 + 51805^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11332014041 is a prime.

It is a super-2 number, since 2×11332014041² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11332014061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666007020 + 5666007021.

It is an arithmetic number, because the mean of its divisors is an integer number (5666007021).

Almost surely, 2^11332014041 is an apocalyptic number.

It is an amenable number.

11332014041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11332014041 is an equidigital number, since it uses as much as digits as its factorization.

11332014041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 11332014041 its reverse (14041023311), we get a palindrome (25373037352).

The spelling of 11332014041 in words is "eleven billion, three hundred thirty-two million, fourteen thousand, forty-one".