Base | Representation |
---|---|
bin | 10101000110111000… |
… | …01110011111011011 |
3 | 1002020202012021022101 |
4 | 22203130032133123 |
5 | 141201444121222 |
6 | 5112244304231 |
7 | 550550403505 |
oct | 124334163733 |
9 | 32222167271 |
10 | 11332020187 |
11 | 48956a2544 |
12 | 22430a2077 |
13 | 10b7956ab7 |
14 | 79701ad75 |
15 | 464cc5927 |
hex | 2a370e7db |
11332020187 has 2 divisors, whose sum is σ = 11332020188. Its totient is φ = 11332020186.
The previous prime is 11332020181. The next prime is 11332020239. The reversal of 11332020187 is 78102023311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11332020187 - 27 = 11332020059 is a prime.
It is a super-3 number, since 3×113320201873 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11332020181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666010093 + 5666010094.
It is an arithmetic number, because the mean of its divisors is an integer number (5666010094).
Almost surely, 211332020187 is an apocalyptic number.
11332020187 is a deficient number, since it is larger than the sum of its proper divisors (1).
11332020187 is an equidigital number, since it uses as much as digits as its factorization.
11332020187 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 28.
Adding to 11332020187 its reverse (78102023311), we get a palindrome (89434043498).
The spelling of 11332020187 in words is "eleven billion, three hundred thirty-two million, twenty thousand, one hundred eighty-seven".
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