Base | Representation |
---|---|
bin | 100101001100100100110… |
… | …0000010111100101100111 |
3 | 200002201121002120120102012 |
4 | 1022121021200113211213 |
5 | 1132224334020213411 |
6 | 14512311013304435 |
7 | 1035230115414461 |
oct | 112311140274547 |
9 | 20081532516365 |
10 | 5112244304231 |
11 | 16a10aa6a7659 |
12 | 6a695433511b |
13 | 2b110c53552c |
14 | 139610a5b131 |
15 | 8ceab88818b |
hex | 4a649817967 |
5112244304231 has 2 divisors, whose sum is σ = 5112244304232. Its totient is φ = 5112244304230.
The previous prime is 5112244304227. The next prime is 5112244304267. The reversal of 5112244304231 is 1324034422115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5112244304231 - 22 = 5112244304227 is a prime.
It is a super-2 number, since 2×51122443042312 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5112244301231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556122152115 + 2556122152116.
It is an arithmetic number, because the mean of its divisors is an integer number (2556122152116).
Almost surely, 25112244304231 is an apocalyptic number.
5112244304231 is a deficient number, since it is larger than the sum of its proper divisors (1).
5112244304231 is an equidigital number, since it uses as much as digits as its factorization.
5112244304231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 5112244304231 its reverse (1324034422115), we get a palindrome (6436278726346).
The spelling of 5112244304231 in words is "five trillion, one hundred twelve billion, two hundred forty-four million, three hundred four thousand, two hundred thirty-one".
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