Base | Representation |
---|---|
bin | 1010010011100111000111… |
… | …0011011010110010011011 |
3 | 1111010022221212101022010001 |
4 | 2210321301303122302123 |
5 | 2441131000424000243 |
6 | 40033510351433431 |
7 | 2246466225321604 |
oct | 244716163326233 |
9 | 44108855338101 |
10 | 11332033031323 |
11 | 3679985247814 |
12 | 1330282b25877 |
13 | 6427b5888a64 |
14 | 2b268ab38dab |
15 | 149b8b1cba4d |
hex | a4e71cdac9b |
11332033031323 has 2 divisors, whose sum is σ = 11332033031324. Its totient is φ = 11332033031322.
The previous prime is 11332033031279. The next prime is 11332033031351. The reversal of 11332033031323 is 32313033023311.
It is an a-pointer prime, because the next prime (11332033031351) can be obtained adding 11332033031323 to its sum of digits (28).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11332033031323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11332033031291 and 11332033031300.
It is not a weakly prime, because it can be changed into another prime (11332033031353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666016515661 + 5666016515662.
It is an arithmetic number, because the mean of its divisors is an integer number (5666016515662).
Almost surely, 211332033031323 is an apocalyptic number.
11332033031323 is a deficient number, since it is larger than the sum of its proper divisors (1).
11332033031323 is an equidigital number, since it uses as much as digits as its factorization.
11332033031323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 28.
Adding to 11332033031323 its reverse (32313033023311), we get a palindrome (43645066054634).
The spelling of 11332033031323 in words is "eleven trillion, three hundred thirty-two billion, thirty-three million, thirty-one thousand, three hundred twenty-three".
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