Base | Representation |
---|---|
bin | 1010010011100111001000… |
… | …1000100011100100110011 |
3 | 1111010022222020210210221212 |
4 | 2210321302020203210303 |
5 | 2441131003333303324 |
6 | 40033511110310335 |
7 | 2246466323400302 |
oct | 244716210434463 |
9 | 44108866723855 |
10 | 11332038572339 |
11 | 3679988391871 |
12 | 13302849583ab |
13 | 6427b6a78b74 |
14 | 2b268b77c439 |
15 | 149b8b92370e |
hex | a4e72223933 |
11332038572339 has 2 divisors, whose sum is σ = 11332038572340. Its totient is φ = 11332038572338.
The previous prime is 11332038572311. The next prime is 11332038572389. The reversal of 11332038572339 is 93327583023311.
It is an a-pointer prime, because the next prime (11332038572389) can be obtained adding 11332038572339 to its sum of digits (50).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11332038572339 - 212 = 11332038568243 is a prime.
It is not a weakly prime, because it can be changed into another prime (11332038572389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666019286169 + 5666019286170.
It is an arithmetic number, because the mean of its divisors is an integer number (5666019286170).
Almost surely, 211332038572339 is an apocalyptic number.
11332038572339 is a deficient number, since it is larger than the sum of its proper divisors (1).
11332038572339 is an equidigital number, since it uses as much as digits as its factorization.
11332038572339 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2449440, while the sum is 50.
The spelling of 11332038572339 in words is "eleven trillion, three hundred thirty-two billion, thirty-eight million, five hundred seventy-two thousand, three hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •