Base | Representation |
---|---|
bin | 10000011111011000001… |
… | …110010010101100101111 |
3 | 11000022222221021221220112 |
4 | 100133120032102230233 |
5 | 122031300212232421 |
6 | 2224330423010235 |
7 | 144604565163365 |
oct | 20373016225457 |
9 | 4008887257815 |
10 | 1133204024111 |
11 | 3a7653146835 |
12 | 16375789997b |
13 | 82b25bba713 |
14 | 3cbc1267635 |
15 | 1e725a2045b |
hex | 107d8392b2f |
1133204024111 has 2 divisors, whose sum is σ = 1133204024112. Its totient is φ = 1133204024110.
The previous prime is 1133204024107. The next prime is 1133204024149. The reversal of 1133204024111 is 1114204023311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1133204024111 - 22 = 1133204024107 is a prime.
It is a super-4 number, since 4×11332040241114 (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1133204026111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566602012055 + 566602012056.
It is an arithmetic number, because the mean of its divisors is an integer number (566602012056).
Almost surely, 21133204024111 is an apocalyptic number.
1133204024111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133204024111 is an equidigital number, since it uses as much as digits as its factorization.
1133204024111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 1133204024111 its reverse (1114204023311), we get a palindrome (2247408047422).
The spelling of 1133204024111 in words is "one trillion, one hundred thirty-three billion, two hundred four million, twenty-four thousand, one hundred eleven".
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