Base | Representation |
---|---|
bin | 1010010011100111010000… |
… | …1000100011100101000011 |
3 | 1111010100001120221120000012 |
4 | 2210321310020203211003 |
5 | 2441131040431024122 |
6 | 40033514305415135 |
7 | 2246500211531546 |
oct | 244716410434503 |
9 | 44110046846005 |
10 | 11332072126787 |
11 | 36799a531a815 |
12 | 133029403a4ab |
13 | 6427c09c6979 |
14 | 2b2691dd485d |
15 | 149b8e8507e2 |
hex | a4e74223943 |
11332072126787 has 2 divisors, whose sum is σ = 11332072126788. Its totient is φ = 11332072126786.
The previous prime is 11332072126733. The next prime is 11332072126861. The reversal of 11332072126787 is 78762127023311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11332072126787 - 228 = 11331803691331 is a prime.
It is a super-4 number, since 4×113320721267874 (a number of 53 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (11332072026787) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666036063393 + 5666036063394.
It is an arithmetic number, because the mean of its divisors is an integer number (5666036063394).
Almost surely, 211332072126787 is an apocalyptic number.
11332072126787 is a deficient number, since it is larger than the sum of its proper divisors (1).
11332072126787 is an equidigital number, since it uses as much as digits as its factorization.
11332072126787 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1185408, while the sum is 50.
The spelling of 11332072126787 in words is "eleven trillion, three hundred thirty-two billion, seventy-two million, one hundred twenty-six thousand, seven hundred eighty-seven".
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