Base | Representation |
---|---|
bin | 110100110001001110… |
… | …1101100111010100011 |
3 | 101211111112122111020022 |
4 | 1221202131230322203 |
5 | 3324040200244021 |
6 | 124020424304055 |
7 | 11121126324344 |
oct | 1514235547243 |
9 | 354445574208 |
10 | 113321103011 |
11 | 44071898a46 |
12 | 19b6701202b |
13 | a8bc58a70c |
14 | 56b02d40cb |
15 | 2e339681ab |
hex | 1a6276cea3 |
113321103011 has 2 divisors, whose sum is σ = 113321103012. Its totient is φ = 113321103010.
The previous prime is 113321102977. The next prime is 113321103013. The reversal of 113321103011 is 110301123311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113321103011 - 210 = 113321101987 is a prime.
It is a super-2 number, since 2×1133211030112 (a number of 23 digits) contains 22 as substring.
Together with 113321103013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (113321103013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56660551505 + 56660551506.
It is an arithmetic number, because the mean of its divisors is an integer number (56660551506).
Almost surely, 2113321103011 is an apocalyptic number.
113321103011 is a deficient number, since it is larger than the sum of its proper divisors (1).
113321103011 is an equidigital number, since it uses as much as digits as its factorization.
113321103011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 113321103011 its reverse (110301123311), we get a palindrome (223622226322).
The spelling of 113321103011 in words is "one hundred thirteen billion, three hundred twenty-one million, one hundred three thousand, eleven".
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