Base | Representation |
---|---|
bin | 1010010011100111011010… |
… | …0001011011001000110011 |
3 | 1111010100011101100111110021 |
4 | 2210321312201123020303 |
5 | 2441131131210401433 |
6 | 40033522300344311 |
7 | 2246501206254022 |
oct | 244716641331063 |
9 | 44110141314407 |
10 | 11332112200243 |
11 | 3679a15a0057a |
12 | 13302a5545097 |
13 | 6427c90b7a83 |
14 | 2b26974668b9 |
15 | 149b9311922d |
hex | a4e7685b233 |
11332112200243 has 2 divisors, whose sum is σ = 11332112200244. Its totient is φ = 11332112200242.
The previous prime is 11332112200237. The next prime is 11332112200289. The reversal of 11332112200243 is 34200221123311.
11332112200243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11332112200243 - 233 = 11323522265651 is a prime.
It is a super-3 number, since 3×113321122002433 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11332112207243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666056100121 + 5666056100122.
It is an arithmetic number, because the mean of its divisors is an integer number (5666056100122).
Almost surely, 211332112200243 is an apocalyptic number.
11332112200243 is a deficient number, since it is larger than the sum of its proper divisors (1).
11332112200243 is an equidigital number, since it uses as much as digits as its factorization.
11332112200243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11332112200243 its reverse (34200221123311), we get a palindrome (45532333323554).
The spelling of 11332112200243 in words is "eleven trillion, three hundred thirty-two billion, one hundred twelve million, two hundred thousand, two hundred forty-three".
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