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11332230203131 is a prime number
BaseRepresentation
bin1010010011100111110110…
…0011100100011011111011
31111010100110121101122222121
42210321331203210123323
52441131401413000011
640033542113502111
72246504141256535
oct244717543443373
944110417348877
1011332230203131
113679a76578922
121330318b71937
13642817692976
142b26a8dc2855
15149b9d677e71
hexa4e7d8e46fb

11332230203131 has 2 divisors, whose sum is σ = 11332230203132. Its totient is φ = 11332230203130.

The previous prime is 11332230203113. The next prime is 11332230203137. The reversal of 11332230203131 is 13130203223311.

Together with previous prime (11332230203113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11332230203131 - 213 = 11332230194939 is a prime.

It is a super-2 number, since 2×113322302031312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11332230203096 and 11332230203105.

It is not a weakly prime, because it can be changed into another prime (11332230203137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666115101565 + 5666115101566.

It is an arithmetic number, because the mean of its divisors is an integer number (5666115101566).

Almost surely, 211332230203131 is an apocalyptic number.

11332230203131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11332230203131 is an equidigital number, since it uses as much as digits as its factorization.

11332230203131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 11332230203131 its reverse (13130203223311), we get a palindrome (24462433426442).

The spelling of 11332230203131 in words is "eleven trillion, three hundred thirty-two billion, two hundred thirty million, two hundred three thousand, one hundred thirty-one".