Base | Representation |
---|---|
bin | 10101000110111010… |
… | …00010101100110001 |
3 | 1002020202121010122121 |
4 | 22203131002230301 |
5 | 141202022442113 |
6 | 5112253034241 |
7 | 550552254121 |
oct | 124335025461 |
9 | 32222533577 |
10 | 11332234033 |
11 | 489582917a |
12 | 2243185981 |
13 | 10b7a00233 |
14 | 797074c81 |
15 | 464d18e8d |
hex | 2a3742b31 |
11332234033 has 2 divisors, whose sum is σ = 11332234034. Its totient is φ = 11332234032.
The previous prime is 11332234013. The next prime is 11332234091. The reversal of 11332234033 is 33043223311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11322449649 + 9784384 = 106407^2 + 3128^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11332234033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11332233989 and 11332234007.
It is not a weakly prime, because it can be changed into another prime (11332234013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666117016 + 5666117017.
It is an arithmetic number, because the mean of its divisors is an integer number (5666117017).
Almost surely, 211332234033 is an apocalyptic number.
It is an amenable number.
11332234033 is a deficient number, since it is larger than the sum of its proper divisors (1).
11332234033 is an equidigital number, since it uses as much as digits as its factorization.
11332234033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 25.
Adding to 11332234033 its reverse (33043223311), we get a palindrome (44375457344).
The spelling of 11332234033 in words is "eleven billion, three hundred thirty-two million, two hundred thirty-four thousand, thirty-three".
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