Base | Representation |
---|---|
bin | 11001110001000110010100… |
… | …011110000001101011110111 |
3 | 112212020210011020122100110111 |
4 | 121301012110132001223313 |
5 | 104323210003432113101 |
6 | 1041004513552203451 |
7 | 32604322113636445 |
oct | 3161062436015367 |
9 | 485223136570414 |
10 | 113325203004151 |
11 | 33121a48794216 |
12 | 10863225239587 |
13 | 4b306a0232c68 |
14 | 1ddad7d287b95 |
15 | d17cae037251 |
hex | 671194781af7 |
113325203004151 has 2 divisors, whose sum is σ = 113325203004152. Its totient is φ = 113325203004150.
The previous prime is 113325203004137. The next prime is 113325203004239. The reversal of 113325203004151 is 151400302523311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113325203004151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113325203007151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56662601502075 + 56662601502076.
It is an arithmetic number, because the mean of its divisors is an integer number (56662601502076).
Almost surely, 2113325203004151 is an apocalyptic number.
113325203004151 is a deficient number, since it is larger than the sum of its proper divisors (1).
113325203004151 is an equidigital number, since it uses as much as digits as its factorization.
113325203004151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 113325203004151 its reverse (151400302523311), we get a palindrome (264725505527462).
The spelling of 113325203004151 in words is "one hundred thirteen trillion, three hundred twenty-five billion, two hundred three million, four thousand, one hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •