113330100113 has 2 divisors, whose sum is σ = 113330100114. Its totient is φ = 113330100112.

The previous prime is 113330100083. The next prime is 113330100127. The reversal of 113330100113 is 311001033311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 94293827329 + 19036272784 = 307073^2 + 137972^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113330100113 is a prime.

It is a super-2 number, since 2×113330100113² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113330100091 and 113330100100.

It is not a weakly prime, because it can be changed into another prime (113330100133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56665050056 + 56665050057.

It is an arithmetic number, because the mean of its divisors is an integer number (56665050057).

Almost surely, 2^113330100113 is an apocalyptic number.

It is an amenable number.

113330100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

113330100113 is an equidigital number, since it uses as much as digits as its factorization.

113330100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 113330100113 its reverse (311001033311), we get a palindrome (424331133424).

The spelling of 113330100113 in words is "one hundred thirteen billion, three hundred thirty million, one hundred thousand, one hundred thirteen".