113330100127 has 2 divisors, whose sum is σ = 113330100128. Its totient is φ = 113330100126.

The previous prime is 113330100113. The next prime is 113330100133. The reversal of 113330100127 is 721001033311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113330100127 is a prime.

It is a super-2 number, since 2×113330100127² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113330100098 and 113330100107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113330100167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56665050063 + 56665050064.

It is an arithmetic number, because the mean of its divisors is an integer number (56665050064).

Almost surely, 2^113330100127 is an apocalyptic number.

113330100127 is a deficient number, since it is larger than the sum of its proper divisors (1).

113330100127 is an equidigital number, since it uses as much as digits as its factorization.

113330100127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 378, while the sum is 22.

Adding to 113330100127 its reverse (721001033311), we get a palindrome (834331133438).

The spelling of 113330100127 in words is "one hundred thirteen billion, three hundred thirty million, one hundred thousand, one hundred twenty-seven".