Base | Representation |
---|---|
bin | 10000011111011110000… |
… | …000010011110100111101 |
3 | 11000100020200210222000102 |
4 | 100133132000103310331 |
5 | 122032000030201023 |
6 | 2224344210010445 |
7 | 144610153513166 |
oct | 20373600236475 |
9 | 4010220728012 |
10 | 1133301022013 |
11 | 3a76a2977796 |
12 | 163784276a25 |
13 | 82b4001c924 |
14 | 3cbd00b676d |
15 | 1e72e2d0628 |
hex | 107de013d3d |
1133301022013 has 2 divisors, whose sum is σ = 1133301022014. Its totient is φ = 1133301022012.
The previous prime is 1133301021991. The next prime is 1133301022031. The reversal of 1133301022013 is 3102201033311.
Together with next prime (1133301022031) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 912947763289 + 220353258724 = 955483^2 + 469418^2 .
It is a cyclic number.
It is not a de Polignac number, because 1133301022013 - 224 = 1133284244797 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1133301022093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566650511006 + 566650511007.
It is an arithmetic number, because the mean of its divisors is an integer number (566650511007).
Almost surely, 21133301022013 is an apocalyptic number.
It is an amenable number.
1133301022013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133301022013 is an equidigital number, since it uses as much as digits as its factorization.
1133301022013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 1133301022013 its reverse (3102201033311), we get a palindrome (4235502055324).
The spelling of 1133301022013 in words is "one trillion, one hundred thirty-three billion, three hundred one million, twenty-two thousand, thirteen".
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