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11333010220130 = 251133301022013
BaseRepresentation
bin1010010011101010110000…
…0011000110010001100010
31111010102110222010122011002
42210322230003012101202
52441140001104021010
640034151340152002
72246532362304554
oct244725403062142
944112428118132
1011333010220130
11367a336900175
1213304b6238602
1364291016a0a1
142b27408294d4
15149be6da41a5
hexa4eac0c6462

11333010220130 has 8 divisors (see below), whose sum is σ = 20399418396252. Its totient is φ = 4533204088048.

The previous prime is 11333010220111. The next prime is 11333010220139. The reversal of 11333010220130 is 3102201033311.

It can be written as a sum of positive squares in 2 ways, for example, as 11128008641689 + 205001578441 = 3335867^2 + 452771^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is not an unprimeable number, because it can be changed into a prime (11333010220139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 566650510997 + ... + 566650511016.

Almost surely, 211333010220130 is an apocalyptic number.

11333010220130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11333010220130 is a deficient number, since it is larger than the sum of its proper divisors (9066408176122).

11333010220130 is a wasteful number, since it uses less digits than its factorization.

11333010220130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1133301022020.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 11333010220130 its reverse (3102201033311), we get a palindrome (14435211253441).

The spelling of 11333010220130 in words is "eleven trillion, three hundred thirty-three billion, ten million, two hundred twenty thousand, one hundred thirty".

Divisors: 1 2 5 10 1133301022013 2266602044026 5666505110065 11333010220130