Base | Representation |
---|---|
bin | 1010010011101011011110… |
… | …0010100101010011111111 |
3 | 1111010102222101221001002221 |
4 | 2210322313202211103333 |
5 | 2441140344433214403 |
6 | 40034222424430211 |
7 | 2246540223145423 |
oct | 244726742452377 |
9 | 44112871831087 |
10 | 11333203023103 |
11 | 367a425717975 |
12 | 133054a918367 |
13 | 6429410a45a0 |
14 | 2b275c296b83 |
15 | 149c08c8adbd |
hex | a4eb78a54ff |
11333203023103 has 32 divisors (see below), whose sum is σ = 13618084919040. Its totient is φ = 9317540574720.
The previous prime is 11333203023101. The next prime is 11333203023151. The reversal of 11333203023103 is 30132030233311.
It is a cyclic number.
It is not a de Polignac number, because 11333203023103 - 21 = 11333203023101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11333203023101) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2320608 + ... + 5296378.
It is an arithmetic number, because the mean of its divisors is an integer number (425565153720).
Almost surely, 211333203023103 is an apocalyptic number.
11333203023103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11333203023103 is a deficient number, since it is larger than the sum of its proper divisors (2284881895937).
11333203023103 is a wasteful number, since it uses less digits than its factorization.
11333203023103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2976727.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 11333203023103 its reverse (30132030233311), we get a palindrome (41465233256414).
The spelling of 11333203023103 in words is "eleven trillion, three hundred thirty-three billion, two hundred three million, twenty-three thousand, one hundred three".
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