Base | Representation |
---|---|
bin | 11001110001001100101111… |
… | …101000101011011010110011 |
3 | 112212021102221222212122112012 |
4 | 121301030233220223122303 |
5 | 104323313120403413212 |
6 | 1041012014253153135 |
7 | 32604655055624006 |
oct | 3161145750533263 |
9 | 485242858778465 |
10 | 113332101232307 |
11 | 33124968647121 |
12 | 1086462b48b7ab |
13 | 4b3122c424a79 |
14 | 1ddb4354b153d |
15 | d1806494b922 |
hex | 67132fa2b6b3 |
113332101232307 has 2 divisors, whose sum is σ = 113332101232308. Its totient is φ = 113332101232306.
The previous prime is 113332101232213. The next prime is 113332101232321. The reversal of 113332101232307 is 703232101233311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113332101232307 - 216 = 113332101166771 is a prime.
It is a super-3 number, since 3×1133321012323073 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (113332101232807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56666050616153 + 56666050616154.
It is an arithmetic number, because the mean of its divisors is an integer number (56666050616154).
Almost surely, 2113332101232307 is an apocalyptic number.
113332101232307 is a deficient number, since it is larger than the sum of its proper divisors (1).
113332101232307 is an equidigital number, since it uses as much as digits as its factorization.
113332101232307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13608, while the sum is 32.
Adding to 113332101232307 its reverse (703232101233311), we get a palindrome (816564202465618).
The spelling of 113332101232307 in words is "one hundred thirteen trillion, three hundred thirty-two billion, one hundred one million, two hundred thirty-two thousand, three hundred seven".
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